Question

Find the value of x and y and find the relation between them

Answer 1

Answer:

Let P(x , y) , Q( 3, 6) and T( -3 , 4)

A/C to question ,

PQ = PT

√{(x -3)² + (y -6)² } = √{(x +3)² + (y-4)²}

take square both sides,

(x-3)² + ( y -6)² = (x +3)² + (y-4)²

-6x + 9 -12y + 36 = 6x + 9 -8y + 16

-12x -4y + 20 = 0

3x + y = 5

Answer 2

$\huge\mathfrak\red{\star{\underline{\underline{Answer}}}}$

From where we have to find the value of x and y....

Sryy for this inconvenience