Find the value of x and y and find the relation between them.
Answers
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Step-by-step explanation:
Let the point P(x,y) is equidistant from the points A(3,6)and B(−3,4)
∴PA= PB
By using the distance formula
=
(x
2
−x
1
)
2
+(y
2
−y
1
)
2
we have
⇒
(x−3)
2
+(y−6)
2
=
(x+3)
2
+(y−4)
2
⇒(x−3)
2
+(y−6)
2
=(x+3)
2
+(y−4)
2
⇒x
2
−6x+9+y
2
−12y+36=x
2
+6x+9+y
2
−8y+16
⇒−6x−6x−12y+8y+36−16=0
⇒−12x−4y+20=0
⇒3x+y−5=0
Hence this is a relation between x and y.
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