Find the value of x and y and z
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hope it help you.....
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here,
6y-2= 62.....( alternate angles )
(or) 6y= 62-2
y= 60/6
y= 10
3x+2+6y-2=180....( angle on same segment)
3x+2+60-2=180
3x+60=180
3x=120
x=40
6y-2= 62.....( alternate angles )
(or) 6y= 62-2
y= 60/6
y= 10
3x+2+6y-2=180....( angle on same segment)
3x+2+60-2=180
3x+60=180
3x=120
x=40
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