Question

find the value of x and y by elimination method 4x-y=60 , x-y=3​

Answer 1

Step-by-step explanation:

Step 1: Multiply each equation by a suitable number so that the two equations have the same leading coefficient. ...

Step 2: Subtract the second equation from the first.

Step 3: Solve this new equation for y.

Step 4: Substitute y = 2 into either Equation 1 or Equation 2 above and solve for x.

Answer 2

$\sf{\underline{Given\:Equations}}$

4x-y = 60

x-y = 3

$\sf{\underline{To\:Find}}$

The value of x and y

$\sf{\underline{Method\:to\:be\:used}}$

Elimination method.

$\sf{\underline{Solution}}$

$\sf{4x - y = 60 \longrightarrow [i]}$

$\sf{x-y = 3 \longrightarrow [ii]}$

Now,

Multiply the Eq.[i] by 1 and Eq.[ii] by 4

= $\sf{4x-y = 60 ----- [i]\times1}$

= $\sf{x-y = 3 -------- [ii]\times4}$

= $\sf{4x - y = 60\longrightarrow[iii]}$

= $\sf{4x - 4y = 12\longrightarrow[iv]}$

Now subtracting Eq.[iii] and Eq.[iv]

= $\sf{(4x-y)-(4x-4y) = (60)-(12)}$

= $\sf{4x-y-4x+4y = 60-12}$

= $\sf{-y + 4y = 48}$

= $\sf{3y = 48}$

= $\sf{y = \dfrac{48}{3}}$

= $\sf{y = 16}$

Putting the value of x in eq.[i]

$\sf{4x - y = 60}$

= $\sf{4x - 16 = 60}$

= $\sf{4x = 60+16}$

= $\sf{4x = 76}$

= $\sf{x = \dfrac{76}{4}}$

= $\sf{x = 19}$

Therefore,

${\underline{\boxed{\sf{x = 19}}}}$

${\underline{\boxed{\sf{y = 16}}}}$

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