find the value of x and y by elimination process 3x-5y=6, 2x+3y=61
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3x-5y=6 ..... 1
2x+3y=61 .....2
multiplying equation by 1 by 3 and equation 2 by 5 we get ,
3(3x-5y)= 6(3) .......3 or 9x-15y=18
5(2x-3y)=61(5) ........4 or 10x-15y=305
subtracting equation 3 by equation 4 we get ,
10x-15y-(9x-15y)=305-18
or x=287
sustituting x=287 in equation 1 we get ,
3(287)-5y=6
or 861-5y=6
or -5y= -855
therefore, y=171
x= 287
hoped it helped
2x+3y=61 .....2
multiplying equation by 1 by 3 and equation 2 by 5 we get ,
3(3x-5y)= 6(3) .......3 or 9x-15y=18
5(2x-3y)=61(5) ........4 or 10x-15y=305
subtracting equation 3 by equation 4 we get ,
10x-15y-(9x-15y)=305-18
or x=287
sustituting x=287 in equation 1 we get ,
3(287)-5y=6
or 861-5y=6
or -5y= -855
therefore, y=171
x= 287
hoped it helped
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