find the value of X and Y from the equal ordered pairs
(x+y,3x-2y) = (16,12)
Answers
Answered by
260
Answer:
x+y = 16 .......(1)
3x-2y = 12
multiply 2 in eq 1 and add both
2x+2y = 32
3x-2y = 12
we get 5x = 44
x = 44/5
Put x in eq 1
y = 16-44/5 = 80-44/5 = 36/5
Answered by
7
Answer:
x+y=16,3x-2y=12
3x-x+2y-y=16+12
2x+y=28
x+y=28/2
x+y=14
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