Question

Find the value of x and y from the following equal ordered pairs. a) (2x-1, y+2) = (-1, 2) b) (x+y, x-y) = (8, 0) c) (2^{x+y}, 2^{x-y}) = (16, 1) d) \sqrt[x]{4}, \sqrt[y]{9} = (\frac{1}{2}, \frac{1}{3})

Answer 1

Answer:

a) x = 0, y = 0

b) x = 4, y = 4

c) x = 2, y = 2

Step-by-step explanation:

a) (2x-1, y+2) = (-1, 2)

2x - 1 = -1

2x = 0

x = 0

y + 2 = 2

y = 0

b) (x+y, x-y) = (8, 0)

x + y = 8

x - y = 0

x = 4

y = 4

c) (2^{x+y}, 2^{x-y}) = (16, 1)

2^{x+y} = 2^4

x + y = 4

2^{x-y} = 1

x - y = 0

x = 2

y = 2

d) The question is not clear