find the value of x and y if (2+3x)+(4y+5)i=0
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Answered by
4
(2+3x)+(4y+5)=0
= 2+3x+4y+5=0
= 7+3x+4y=0
if the value of x=1
then, 7+3×1+4y=0
= 7+3+4y=0
= y = -10/4= -2.5 or -5/2
hence, x = 1
and y= -2.5
= 2+3x+4y+5=0
= 7+3x+4y=0
if the value of x=1
then, 7+3×1+4y=0
= 7+3+4y=0
= y = -10/4= -2.5 or -5/2
hence, x = 1
and y= -2.5
Answered by
1
( 2 + 3x ) + (4y + 5 ) (-1) = 0
2 + 3x -4y - 5 = 0
3x - 4y - 3 = 0
The above equation is a linear equation in two variables, it has infinite number of solutions.
It has infinite values of x, y which can satisfy the equation.
Some solutions are
( 1 , 0 )
( 0 , - 3/4 )
2 + 3x -4y - 5 = 0
3x - 4y - 3 = 0
The above equation is a linear equation in two variables, it has infinite number of solutions.
It has infinite values of x, y which can satisfy the equation.
Some solutions are
( 1 , 0 )
( 0 , - 3/4 )
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