Question

Find the value of x and y if:

3^x-1 = 9 & 4^y+2 = 64

Answer 1

Answer:

x=3

y=1

Step-by-step explanation:

${3}^{x - 1} = 9 \: \: \: \: \: and \: {4}^{y + 2} = 64$

${3}^{x - 1} = {3}^{2} \: \: \: \: and \: {4}^{y + 2} = {4}^{3}$

as their base is the same

${x - 1} = {2} \: \: \: \: and \: {y + 2} = {3}$

${x} = {3} \: \: \: \: and \: {y} = {1}$

Answer 2

Answer:

x=3 , y=1

Step-by-step explanation:

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