find the value of x and y , if B || CD and AG || CF
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Correct option is
D
105
∘
Extend the line EF to H so that HG∣∣AC
Now HG∣∣AC and BC is transversal
∠BGH=∠BCA (Corresponding angles)
∠BGH=65
∘
Now exterior angle of triangle is equal to sum of interior opposite angles
Applying the same in △BGH
∠HBG+∠BGH=∠GHA
40
∘
+65
∘
=y
y=105
∘
Now AB||FCFandHE$$ is transversal
∴x=y (corresponding angles)
x=105
∘
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