find the value of x and y if (x+2y)+(2x-3y)i+4i=5
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equating the real part and imaginary part
x+2y=0 -----1
2x-3y+4=5
2x-3y=1
multiplying first eq by 2
2x+4y=0
2x-3y=1
subtracting these eq
7y=-1
y=-1/7
putting this value in eq 1
x-2/7=0
x=2/7
x+2y=0 -----1
2x-3y+4=5
2x-3y=1
multiplying first eq by 2
2x+4y=0
2x-3y=1
subtracting these eq
7y=-1
y=-1/7
putting this value in eq 1
x-2/7=0
x=2/7
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