Find the value of x and y if x+3,y+7,x+y+8,x+3y+20 are in Ap
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Answered by
3
Answer:
x+y+8-(x+3)=2[x+3y+20-(x+y+8)]
y+5=2[2y+12]
y+5=4y+24
3y=-19
y=-19/3
x+y+8-(y+7)=2y+12
x+1=2y+12
x=2y+11
x=2(-19/3)+11
x=11-38/3
x=-5/3
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Answered by
1
Answer:
x+y+8-(x+3)=2[x+3y+20-(x+y+8)]
y+5=2[2y+12]
y+5=4y+24
3y=-19
y=-19/3
x+y+8-(y+7)=2y+12
x+1=2y+12
x=2y+11
x=2(-19/3)+11
x=11-38/3
x=-5/3
Step-by-step explanation:
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