Question

Find the value of x and y if x+3,y+7,x+y+8,x+3y+20 are in Ap

Answer 1

Answer:

x+y+8-(x+3)=2[x+3y+20-(x+y+8)]

y+5=2[2y+12]

y+5=4y+24

3y=-19

y=-19/3

x+y+8-(y+7)=2y+12

x+1=2y+12

x=2y+11

x=2(-19/3)+11

x=11-38/3

x=-5/3

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Answer 2

Answer:

x+y+8-(x+3)=2[x+3y+20-(x+y+8)]

y+5=2[2y+12]

y+5=4y+24

3y=-19

y=-19/3

x+y+8-(y+7)=2y+12

x+1=2y+12

x=2y+11

x=2(-19/3)+11

x=11-38/3

x=-5/3

Step-by-step explanation: