find the value of x and y in 2 x - 3 Y - 1= 0 and X + 2 Y - 4
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2x - 3y - 1 = 0. (eq 1)
x + 2y - 4 = 0. (eq 2)
2x - 3y - 1 = 0
x + 2y - 4 = 0
(-) (-) (+)
x + y + 5
x=5 - y
Substitute x = 5 - y in eq 1 , we get
2 (5 - y ) - 3y - 1 = 0
10 - 2y - 3y - 1 = 0
10 - y - 1 = 0
9 - y = 0
y = -9
Place y = -9 in eq 2 , we get
x + 2 × (-9) - 4 = 0
x - 18 - 4 = 0
x - 22 = 0
x = 22
Hence , the value of x and y is
x = 22
y = -9
Hope it will help u
Thank u
x + 2y - 4 = 0. (eq 2)
2x - 3y - 1 = 0
x + 2y - 4 = 0
(-) (-) (+)
x + y + 5
x=5 - y
Substitute x = 5 - y in eq 1 , we get
2 (5 - y ) - 3y - 1 = 0
10 - 2y - 3y - 1 = 0
10 - y - 1 = 0
9 - y = 0
y = -9
Place y = -9 in eq 2 , we get
x + 2 × (-9) - 4 = 0
x - 18 - 4 = 0
x - 22 = 0
x = 22
Hence , the value of x and y is
x = 22
y = -9
Hope it will help u
Thank u
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