find the value of x and y in the following figure
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x =70
because of supplementary property (180-110=70)
y=40
because sum of angles of quadrilateral is 360.so 60+x+y+90 =360
60+70+90+y= 360
220+y=360
y=360-220
y=140
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x=180°-110°
x=70°
Angle BCD=90°
And, sum of angles of quadrilateral=360°
A+B+C+D=360°
60°+y+90°+70°=360°
y+220°=360°
y=360°-220°
y=140°
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