Find the value of x and y in the following figure where ABCD is a parallelogram.
Attachments:
Answers
Answered by
185
Here, 2(x + 1) = 3x - 1 (As diagonals bisects)
or, 2x + 2 = 3x - 1
or, x= 3
Again, 5y + 1 =6y - 1
or, y = 2
Hence value of x & y are 3 & 2 respectively.
or, 2x + 2 = 3x - 1
or, x= 3
Again, 5y + 1 =6y - 1
or, y = 2
Hence value of x & y are 3 & 2 respectively.
Answered by
282
Here's your answer, mate☺️
Diagonals of parallelogram bisects each other
thus,
→ 5y+1=6y-1
→ 1+1 = 6y-5y
→ 2= y
thus value of y is 2
now, equating the value of x
→ 3x-1 = 2(x+1)
→ 3x-1 = 2x+2
→ 3x-2x = 2+1
→ x = 3
thus, value of x is 3
Ans: The value of x and y is 3 and 2 respectively
hope it helps!
mark it as brainliest ✌️✌️
Diagonals of parallelogram bisects each other
thus,
→ 5y+1=6y-1
→ 1+1 = 6y-5y
→ 2= y
thus value of y is 2
now, equating the value of x
→ 3x-1 = 2(x+1)
→ 3x-1 = 2x+2
→ 3x-2x = 2+1
→ x = 3
thus, value of x is 3
Ans: The value of x and y is 3 and 2 respectively
hope it helps!
mark it as brainliest ✌️✌️
Similar questions