Find the value of x and y in the following figures:
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For 1st part
ABC is a isosceles triangle
So angle y = angle ACB
Angle y + Angle ACB = 180° ( linear pair )
Angle ACB = 180°-120° = 60°
So angle y also = 60°
Angle x + Angle y = 120°. ( exterior angle sum theorem )
Angle x = 120°-60°
Angle x + 60° = 120°
Angle x = 60°
For part ii)
Here Angle BAC = 80° ( vertically opposite angles )
Angle y + Angle ACB + Angle BAC = 180° ( sum of angles of ∆ )
Angel y + Angle ACB = 180°-80° = 100°
But Angle y = Angle ACB ( Isosceles ∆ )
Angle y = 100°/2 = 50° ( Angle ACB also 50° )
Angle ACB + Angle x = 180° ( linear pair )
50° + Angle x = 180°
Angle x = 180°-50°
= 130 °
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