Question

find the value of x and y in the following isosceles triangles​

Answer 1

First, let us name the triangle as ABC.

And then, let us name the 3rd angle in that triangle as ∠y and ∠112° as ∠z.

∠y and ∠z are complementary angles.

So,

= ∠y + ∠z = 180°

= ∠y + 112° = 180°

= ∠y = 180° - 112°

= ∠y = 68°

The sum of all angles of triangle is 180°.

So,

In triangle ABC,

= ∠x + ∠x + ∠y = 180°

= 2x + 68° = 180°

= 2x = 180° - 68°

= ∠x = $\frac{112}{2}$

= ∠x = 56°