find the value of x and y in the following parallelogram.
please explain in detail...
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The sum of adjacent angles of Quadrilateral is 180°. So,
120°-x+y=180°
-x+y=60° ---eq(1)
x-80°+y=180°
x+y=260° ---eq(2)
From (1) subtracting (2)
-x+y=60°
x+y=260°
- - -
-2x = -200°
x=100°
100°+y=260°
y=160°
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