Question

Find the value of x and y in the following parallelogram.

please explain in detail...

Answer 1

☛ On the line BD

$\bf \large \hookrightarrow \: 20 \degree = 2x + 4 \\ \\ \bf \large \hookrightarrow \: 2x = 20 \: - \: 4 \\ \\ \bf \large \hookrightarrow \: 2x = 16 \\ \\ \bf \large \hookrightarrow \: x = \frac{16}{2} \\ \\ \bf \large \hookrightarrow \: x = 8$

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☛ On the line AC

$\bf \large \hookrightarrow \: 22 = x \: + \: y$

• We know that, the value of x is 8.

• Now, we put the value of x in the given equation.

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$\bf \large \hookrightarrow \: 22 \: = \: 8 \: + \: y \\ \\ \bf \large \hookrightarrow \: 22 \: - \: 8 = y \\ \\ \bf \large \hookrightarrow14 \: = \: y \\ \\ \bf \Large \implies \: Value \: \: of \: \: y \: \: is \: \: 14$

Answer 2

Answer:

On the line BD

\begin{gathered}\bf \large \hookrightarrow \: 20 \degree = 2x + 4 \\ \\ \bf \large \hookrightarrow \: 2x = 20 \: - \: 4 \\ \\ \bf \large \hookrightarrow \: 2x = 16 \\ \\ \bf \large \hookrightarrow \: x = \frac{16}{2} \\ \\ \bf \large \hookrightarrow \: x = 8\end{gathered}

↪20°=2x+4

↪2x=20−4

↪2x=16

↪x=

2

16

↪x=8

On the line AC

↪22=x+y

We know that, the value of x is 8.

Now, we put the value of x in the given equation.