find the value of x and y in the following parallelogram plz give me full explanation step to step
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y+56=125
=>y= 125-56
=> y = 69(in parallelogram quadrilateral opposite angle are equal)
hence ,,,,, x= 360-(125+111+69)
=>>>> x= 360-305
====>>> x= 55 hope it helps you ..
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=>y= 125-56
=> y = 69(in parallelogram quadrilateral opposite angle are equal)
hence ,,,,, x= 360-(125+111+69)
=>>>> x= 360-305
====>>> x= 55 hope it helps you ..
follow me please
rajkumar3964:
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Answer:
Step-by-step explanation:
1] Opposite angles of Parallelogram ABCD are congruent.
Angle DAB = Angle DCB
125 = Y + 56
Y = 125 - 56
Y = 69°
2] The sum of angle of quadrilateral trapezium ABEC is 360°.
Angle BAE + Angle AEC + Angle ECB + Angle CBA = 360°
125 + 111 + 69 + X = 360
X = 360 - 305
X = 55°
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