find the value of x and y in the following rectangle
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Answered by
1
Answer:
In a rectangle opp sides are equal
x+3y=13 and 3x+y=7
solving these equations
multiplying equation one with 3
3x+9y=39
3x+y=7
3x gets cancel
8y=32
y=32/8=4
substituting y value in one equation
x+3(4) =13
x=13-12=1
Answered by
0
Answer:
Use the perimeter formula of Rectangle.
AB + BC = CD + DA
(X + 3Y) + (3X + Y) = 13 + 7
4X + 4Y = 20
X + Y = 20/4+4
X + Y = 5/4
X = 5
Y = 4
OPTION (C) IS CORRECT
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