Question

Find the value of x and y in the given figure.​

Answer 1

Answer:

FROM, ∆ RPQ,<RPQ=90°

<RQP= 30°

NOW, <RPQ+<RQP+<PRQ= 180°

= 90°+30°+Y= 180°

= Y= 180°-120°

Y= 60°

now, x+y= 180°

= x+60° = 180°

= x= 180°-60°

x= 120°

x= 120°, y= 60°

Answer 2

$\huge\bf\underbrace\red{Answer}$

First find the value of y.

Angle sum property of triangle = Sum of all sides.

⟹ 30 + 90 + y = 180

⟹ 120 + y = 180

⟹ y = 180 − 120 = 60

⟹ y = 60°

X = Sum of opposite side if triangle .

⟹ x = 30 + 90

⟹ x = 120°