Find the value of x and y in triangle ABC if angle B 38° and one exterior angle is 115°.
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Answered by
3
Let's firstly find the value of y.
∠B + ∠C = ∠A [An exterior angle of a triangle is equal to the sum of the two opposite interior angles.]
⇒ 38° + y = 115°
⇒ y = 115° - 38°
⇒ y = 77°
Now we find the value of x.
∠A + ∠B + ∠C = 180° [Angle sum property of triangle.]
⇒ x + 38° + y = 180°
⇒ x + 38° + 77° = 180°
⇒ x = 180° - 115°
⇒ x = 65°
∴ x = 65°
∴ y = 77°
Answered by
2
¤ x = 65 and y = 77
☆To find :-
• The value of x and y.
☆Given:-
• ABC= 38° and one exterior angle is 115°
☆Solution:-
• Here,
115+x= 180 ( linear pair)
=>x=180-115
=>x=65
• Therefore, x = 65
• Now ,in triangle ABC
BAC+ABC+BCA=180°
=>X+38+Y =180
=>65+38+Y=180
=>y = 180 - 103
=> y= 77
• Therefore, y =77
☆Hence:-
• The value of x is 65 and y is 77.
hope it helps.... :)
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