Question

find the value of x and y of the palr of linear equations x + 3y = 6 and 2x-3y = 12.
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Answer 1

Answer:

Hope it helped you

Step-by-step explanation:

Consider the given equation.

x+3y=6             …….. (1)

2x−3y=12           ……… (2)

 On adding both equation (1) and (2), we get

3x=18

x=6  

Now, put the value of x in equation (1), we get

6+3y=6

3y=6−6

3y=0

y=0

Hence, the value of x is 6 and y is 0.

Answer 2

Answer:

• Value of x = 6 and y = 0.

Step-by-step explanation:

Given:

• Equation - x + 3y = 6 and 2x - 3y = 12

To Find:

• Value of x and y.

Method used:

• Substitution method.

Now, we will solve these equations,

⇒ x + 3y = 6   __(1)

⇒ 2x - 3y = 12  __(2)

Now, take equation (1)

⇒ x + 3y = 6

⇒ x = 6 - 3y

Put the value of x in equation (2),

⇒ 2x - 3y = 12

⇒ 2(6 - 3y) - 3y = 12

⇒ 12 - 6y - 3y = 12

⇒ -9y = 0

⇒ y = 0

Now, put the value of y in equation (1)

⇒ x + 3y = 6

⇒ x + 3(0) = 6

⇒ x = 6

Hence, Value of x = 6 and y = 0.