Question

Find the value of x and y which satisfy the following equations:

3x + 2y = 11 and 2x + 3y = 4.

Answer 1

Answer:

Ans of second one is

x=2&Y=0

Step-by-step explanation:

(2×2) + (3×0) = 4

4+0=4

4 = 4

hence proved

Answer 2

Step-by-step explanation:

Solve the The Two Simultaneous equation and you will get the answer

3x+2y = 11

2x + 3y= 4

Now multiplying By 2 in 1st equation we get

6x + 4y= 22

Multiplying By 3 in 2nd equation

6x+ 9y = 12

The new equations are

6x+4y = 22

6x+9y = 12

Now Subtracting the new equations we get

-5y = 10

So y = 10/-5

y= -2

Substituting the value of y in 1st equation we get

3x + 2(-2)= 11

3x -4 = 11

3x= 15

x = 5

So values of x and y are 5 and -2

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