Find the value of x
(angle CAO=40°)
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Answer:
The answer will be 40°.
Step-by-step explanation:
Given;
∠CAO=40°
CO is perpendicular to AB.
Since, ∆ABC is in semicircle,
Thus, ∠ACB = 90°
According to angle sum property of triangle, in ∆ACO;
∠A + ∠AOC + ∠ACO = 180°;
40° + 90° + ∠ACO = 180
∠ACO = 50°. (i)
Now, ∠ACB = ∠ACO + ∠OCB;
Thus, ∠ACO + ∠OCB = 90°
50 + x = 90. (from eq. (i))
x = 40°.
That's all.
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