Question

Find the value of x.....answer my question....

Answer 1

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$\frac{7^{2x+1}}{49} = 7^3\\\\\frac{7^{2x+1}}{7^2} = 7^3\\\\7^{2x+1-2} = 7^3\\7^{2x-1 } = 7^3\\\\Comparing \ powers,\\2x-1 = 3\\2x = 4\\\boxed{\boxed{\bold{x = 2}}}$

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Answer 2

Solution :

7^2x+1/49=7^3

7^2x+1/7^2=7^3

7^2x+1=7^3×7^2

As bases are same and power of multiplication is there so powers added.....

7^2x×7^1=7^3+2

7^2x×7=7^5

7^2x=7^5/7^1

As bases are same and power of division is there then powers subtracted....

7^2x=7^5-1

7^2x=7^4

As bases are same then powers evaluate.....

2x=4

x=4/2

x=2 ans.