Question

Find the value of x any of the distance of the point (x, y) from (-2,0) and (2,0) are both 14 units

Answer 1

Distance between two points =(x2−x1)2+(y2−y1)2

(Distance between two points)2 =(x2−x1)2+(y2−y1)2

Therefore, we get

(x+3)2+y2=16

(x+3)2+y2=16

Subtracting above equations we get,

       (x+3)2+y2=16

       _ (x+3)2 _ +y2_=16

       ____________________

            (x+3)2=(x−3)2

              

∴  x=0 and y=±7