Math, asked by QueenNehaKakkar, 11 months ago

find the value of x..



best answer will be marked as brainliest..

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Answered by Anonymous
2

\huge\boxed{\fcolorbox{cyan}{red}{Solution:-}}.

given here .

[ (-6/11)^x] ÷ [ (-6/11)^-²] ^-¹ = [ (-6/11)²]^-³.

[ (-6/11)^x] ÷ [ (-6/11)^-²] ^-¹ = [ (-6/11)²]^-³.↪[ (-6/11)^x] ÷ [ (-6/11)²] = [ (-6/11)^(-6)].

[ (-6/11)^x] ÷ [ (-6/11)^-²] ^-¹ = [ (-6/11)²]^-³.↪[ (-6/11)^x] ÷ [ (-6/11)²] = [ (-6/11)^(-6)].↪[(-6/11)^(x-2)] = [ (-6/11)^(-6)].

[ (-6/11)^x] ÷ [ (-6/11)^-²] ^-¹ = [ (-6/11)²]^-³.↪[ (-6/11)^x] ÷ [ (-6/11)²] = [ (-6/11)^(-6)].↪[(-6/11)^(x-2)] = [ (-6/11)^(-6)].↪(x-2)=-6.

[ (-6/11)^x] ÷ [ (-6/11)^-²] ^-¹ = [ (-6/11)²]^-³.↪[ (-6/11)^x] ÷ [ (-6/11)²] = [ (-6/11)^(-6)].↪[(-6/11)^(x-2)] = [ (-6/11)^(-6)].↪(x-2)=-6.↪x= -6+2.

[ (-6/11)^x] ÷ [ (-6/11)^-²] ^-¹ = [ (-6/11)²]^-³.↪[ (-6/11)^x] ÷ [ (-6/11)²] = [ (-6/11)^(-6)].↪[(-6/11)^(x-2)] = [ (-6/11)^(-6)].↪(x-2)=-6.↪x= -6+2.↪x= -4.

Inportance formula .

if, a^m = a^n , so , m=n.

if, a^m/a^n = a^(m-n).

Hopes its helps u.

@Abhi

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