Question

find the value of x by using quadratic formula 4a2x2+8abx+4b2=0​

Answer 1

Step-by-step explanation:

In 3a 2x2+8abx+4b2=0 Roots are 2a−b±b2−4ac

Roots are = 2×3a2−8ab±(8ab) 2−4×3a2×4b2

Therefore,

6a2−8ab±64a2b2−48a2b2

⇒ 6a 2−8ab±4ab . If 6a 2−8ab−4ab = 6a 2−12ab =a −2b Or 6a 2 −8ab+4ab = 6a 2 −4ab = 3a −2b Then roots are a −2b and 3a−2b.

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