Question

find the value of x. Correct answer only ​

Answer 1

Answer:

$12 \sqrt{12} \times {12}^{ \frac{2}{3} } \times {12}^{ \frac{1}{3} } \div \sqrt{12} = {12}^{x - 2} \\ = > {12}^{ \frac{5}{2} } \div {12}^{ \frac{1}{2} } = {12}^{x - 2} \\ {12}^{2} = {12}^{x - 2} \\ x - 2 = 2 \\ x = 4$

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