Math, asked by tathagata17, 5 hours ago

Find the value of x correct upto two decimal places, if
$\sqrt{2 + x}$
$+ \sqrt{3}$
$= \sqrt{8}$
.
(A) 0.8
(B) - 0.79
(C) 0.79
(D) - 0.8

Answers

Answered by richitha77

4

Answer:

(B) -0.79

Step-by-step explanation:

answer is -0.79

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