Question

find the value of x cube + 7 x square - X + 16 when X is equals to 1 + 2 iota​

Answer 1

Answer:

emiway

Step-by-step explanation:

Answer 2

Answer:

-17+ 24i

Step-by-step explanation:

Question:

x^3+7x^2-X+16 where x=1+2i

Answer:

putting value of x= 1+2i

(1+2i)^3 + 7(1+2i)^2 -(1+2i) +16

1+ 3(2i)+ 3(2i)^2 +(2i)^3+ 7(1+2(2i)+(2i)^2)-(1+2i)+16

since i^2= -1

1+6i+12(-1)+8i^3+ 7(1+4i+4(-1))-1-2i+16

1+6i-12-8i+7+28i-28-1-2i+16

-17+24i