Question

find the value of x cube minus 8 y cube minus 36 x y- 216 when x is equal to 2 Y + 6
urgent

it is a polynomial question

Answer 1

your answer is 0(zero). take a look at picture with the help of (a+b)³= a³+b³+3ab(a+b).
formula used for (2y+6)³

Answer 2

Answer:

The value of polynomial $x^3-8y^3-36xy-216$ when x = 2y + 6 is 0.

Step-by-step explanation:

Given: polynomial $x^3-8y^3-36xy-216$

We have to find the value of polynomial when x = 2y + 6

Consider the given polynomial $x^3-8y^3-36xy-216$

Substitute x = 2y + 6, we get,

$(2y+6)^3-8y^3-36(2y+6)y-216$

Simplify, we get,

Using algebraic identity $(a+b)^3=a^3+b^3+3a^2b+3ab^2$

$(2y)^3+6^3+72y^2+216y-8y^3-36(2y^2+6y)-216$

Simplify further , we get,

$216+72y^2+216y-72y^2-216y-216$

Simplify, we get

$216+72y^2+216y-72y^2-216y-216=0$

Hence, the value of polynomial $x^3-8y^3-36xy-216$ when x = 2y + 6 is 0.