find the value of x cube + y cube -12xy+64 when x+y= -4
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(x+y)³ = x³+y³ +3xy(x+y)
⇒(-4)³ = x³+y³ +3xy(-4)
⇒ -64 = x³+y³ -12xy
A/q
x³+y³ -12xy +64 = (-64)+64 = 0
⇒(-4)³ = x³+y³ +3xy(-4)
⇒ -64 = x³+y³ -12xy
A/q
x³+y³ -12xy +64 = (-64)+64 = 0
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