find the value of x cube + y cube + 15 x y - 125 if X + Y = 25
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(x+y)3 = x3 + y3 + 3xsqy + 3xysq
125 = x3 + y3+ 3xy(x + y)
125 = x3 + y3+ 3xy(5)
125 = x3 + y3+ 15xy
x3 + y3+ 15xy - 125 = 0
125 = x3 + y3+ 3xy(x + y)
125 = x3 + y3+ 3xy(5)
125 = x3 + y3+ 15xy
x3 + y3+ 15xy - 125 = 0
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