find the value of x for the linear equation 2√2x-3y+4=0 corresponding to y=2
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Answer:
X= 1/√2
Step-by-step explanation:
2√2x-3y+4=0
2√2x-3y=-4
putting y=2
2√2x-3(2)=-4
2√2x-6=-4
2√2x=6-4
2√2x=2
X=2/2√2
X= 1/√2
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