Question

Find the value of x for which 1 + 2 + 4 + 8 + 16 = 2^x - 1.​

Answer 1

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$=1 + 2 + 4 + 8 + 16 = {2}^{x} - 1$

$= 31 = {2}^{x} - 1$

$= 31 + 1 = {2}^{x}$

$= 32 = {2}^{x}$

$= 2 \times 2 \times 2 \times 2 \times 2 = {2}^{x}$

$= {2}^{5} = {2}^{x}$

x= 5