Math, asked by dhanyasreeudayan37, 2 months ago

find the value of x for which (2)^3×(-2)^-6= (-2)^2x-1​

Answers

Answered by simransangutra
2

Answer:

am × an = a(m+n) So , we have , (–2)3 × (–2)–6 =(-2)(3)+(-6) = (-2)(-3) Now , we have , (-2)(-3) = (-2)(2x-1) On comparing both the sides , we get -3 = 2x-1 2x = -3 + 1 2x = -2 x = -2/2 = -1 ∴ x = -1Read more on Sarthaks.com - https://www.sarthaks.com/855956/find-the-value-of-x-so-that-2-3-2-6-2-2x-1

Answered by tranquillity
5

Step-by-step explanation:

am × an = a(m+n)

So , we have ,

(–2)3 × (–2)–6 =(-2)(3)+(-6) = (-2)(-3)

Now , we have ,

(-2)(-3) = (-2)(2x-1)

On comparing both the sides ,

we get

-3 = 2x-1

2x = -3 + 1

2x = -2

x = -2/2

= -1

∴ x = -1

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