Question

find the value of x for which (2/5)^4×(2/5)^_7=(2/5)^2x+1​

Answer 1

Answer:

(2/5) ^4×(2\5) ^7=(2/5) ^2x+1

(2/5)^4+7=(2/5)^2x+1

(2/5)^11=(2/5)^2x+1

11=2x+1

11-1=2x

10=2x

10/2=x

5=x

therefore, x=5

Answer 2

Answer: x=5

Step-by-step explanation: due to the property of exponents, you can simplify this to 4 + 7 = 2x+1, therefore, 11-1=2x, 10=2x, x=5