Question

find the value of x for which 2x, (x+10) and (3x+2) are the three consecutive terms of the A. P. ​

Answer 1

Answer:

x=6

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Answer 2

S O L U T I O N :

Given :

We have three terms are three consecutive terms of the AP.

• 1st term, (a1)= 2x
• 2nd term, (a2) = (x + 10)
• 3rd term, (a3) = (3x + 2)

Explanation :

As we know that formula of the common difference:

d = a2 - a1

According to the question :

d = a2 - a1

d = (x + 10) - 2x

d = x + 10 - 2x

d = -x + 10.................(1)

&

d = a3 - a2

d = (3x + 2) - (x + 10)

d = 3x + 2 - x - 10

d = 2x - 8...............(2)

Now, comparing equation (1) & (2), we get;

➟ -x + 10 = 2x - 8

➟ -x - 2x = -8 - 10

➟ -3x = -18

➟ x = -18/-3

➟ x = 6

Thus,

The value of x will be 6 .