Question

find the value of x for which 2x ,(x+10) and (3x+2) are three consecutive terms of an AP.​

Answer 1

Answer:

as the terms 2x ,(x+10) ,(3x+2) are three consecutive terms of an AP

so, the common difference is equal

(x+10)-2x=(3x+2)-(x+10)

=> x+10-2x=3x+2-x-10

=> -x+10=2x-8

=> -x-2x= -8-10

=> -3x= -18

=> x = -18/-3=6

=> x=6