find the value of x for which (4/9)4 (4/9)-7=(4/9)2x-1
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Step-by-step explanation:
(4/9)^4 × (4/9)^ -7 = (4/9)^(2x-1)
L.H.S = (4/9)power {4+(-7)} [identity of exponent that when base are same and power are different and if they are in multiply then powers will add.]
⇒ (4/9)^-3 = (4/9)^(2x - 1) (base same so base can be removed)
⇒ -3 = 2x - 1
⇒ -2 = 2x
⇒ -1 = x
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