Math, asked by shreyabasavaraj5, 6 months ago

find the value of x for which 5^x÷5^-3=5^5

Answers

Answered by gopi236
2

Answer:

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Attachments:
Answered by Aogarro
0

Answer:

Exact Form:

x = − 3 + ln ( 3128 ) ln ( 5 )

Decimal Form:

x = 2.00059619…

Step-by-step explanation:

5 x ÷ 5 − 3 − 3 = 5 ^5

Simplify each term.

5 x + 3 − 3 = 5^ 5

Raise  5  to the power of  5 .

5 x + 3 − 3 = 3125

Move all terms not containing  x  to the right side of the equation.

5 x + 3 = 3128

Take the natural logarithm of both sides of the equation to remove the variable from the exponent.

ln

(

5

x

+

3

)

=

ln

(

3128

)

Expand  

ln

(

5

x

+

3

)

by moving  

x

+

3

outside the logarithm.

( x + 3 ) ln ( 5 ) = ln ( 3128 )

Apply the distributive property.

x

ln

(

5

)

+

3

ln

(

5

)

=

ln

(

3128

)

Move all the terms containing a logarithm to the left side of the equation.

x

ln

(

5

)

+

3

ln

(

5

)

ln

(

3128

)

=

0

Move all terms not containing  

x

to the right side of the equation.

Tap for more steps...

x

ln

(

5

)

= − 3 ln ( 5 ) + ln ( 3128 )

Divide each term by  

ln ( 5 )  and simplify.

Tap for more steps...

x = − 3 + ln ( 3128 ) ln ( 5 )

The result can be shown in multiple forms.

Exact Form:

x = − 3 + ln ( 3128 ) ln ( 5 )

Decimal Form:

x = 2.00059619…

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