find the value of x for which (7/12) power 4 ×(7/12) power 3x =(7/12) power 5
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Given (127)−4×(127)3x=(127)5
Since the base term in equation is same, according to laws of exponents we can equate them as
−4+3x=5
Now shift the −4 to R.H.S it becomes 4
⇒3x=5+4
⇒3x=9
Now sahift 3 to R.H.S
⇒x=39=3
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