Question

Find the value of x for which 7 to the power 10 ÷7 to the Power 8 =(1/7)to the Power x​

Answer 1

Answer:

${7}^{10} \div {7}^{8} = (1 \div 7) {}^{ x} \\ {7}^{10 - 8} = (1 \div 7) {}^{x} \\ {7}^{2} = {7}^{ - 1 \times x} \\ as \: the \: bases \: are \: equal \: then \: powers \: are \: also \: equal \\ 2 = - 1x \\ x = 2 \div - 1 \\ x = - 2$

useful right