Question

Find the value of x for which (8x+4)(6x-2) and (2x+7) are in A.P.

Answer 1

Answer:

The value of x is 15/2.

Step-by-step explanation:

Given :  

(8x + 4)(6x - 2) and (2x + 7) are in A.P.

Since the terms are in A.P

Therefore,  

Second term - first term =  third term - second term

[Common difference in AP is same]

a2 - a1 = a3 - a2

Therefore,

6x - 2 - (8x + 4) = (2x + 7) - (6x - 2)

=> 6x - 2 - 8x - 4 = 2x + 7 - 6x + 2

=> 6x - 8x - 2 - 4 = 2x - 6x + 7 + 2

=> -2x - 6 = - 4x + 9

=> - 2x + 4x = 9 + 6

=> 2x = 15

=>x = 15/2

Hence, the value of x is 15/2.

HOPE THIS ANSWER WILL HELP YOU...

Answer 2

SOLUTION

If the expression are in AP then,

=)(6x-2)-(8x+4)= (2x+7)-(6x-2)

=) 6x-2-8x-4= 2x+7-6x+2

=) -2x-6= -4x+9

=) 2x= 15

=)x= 15/2

=) x= 7.5

hope it helps ✔️