Question

Find the value of x for which (8x+4) (6x-2) and (2x+7) are in
a.P

Answer 1

Step-by-step explanation:

(8x + 4), (6x - 2), (2x + 7)

the series to be in AP common difference should be equal

d = a2 - a1 = a3 - a2

a1 = 8x + 4

a2 = 6x - 2

a3 = 2x + 7

(6x - 2) - (8x + 4) = (2x + 7) - (6x - 2)

6x - 2 - 8x - 4 = 2x + 7 - 6x + 2

-2x - 6 = -4x + 9

-2x + 4x = 9 + 6

2x = 15

x = 15/2

verification

a1 = 8x + 4 = 8(15/2) + 4 = 4(15) + 4 = 60 + 4 = 64

a2 = 6x - 2 = 6(15/2) - 2 = 3(15) - 2 = 45 - 2 = 43

a3 = 2x + 7 = 2(15/2) + 7 = 15 + 7 = 22

the AP is 64, 43, 22

hope you get your answer