Question

Find the value of x for which 8x+4,6x-2 and 2x+7 are in a.p

Answer 1

Answer:

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Answer 2

ANSWER :–

$\\ \longrightarrow \: \: \large{ \green{ \boxed{ \bold {x = \frac{15}{2} }}}}$

EXPLANATION :–

GIVEN :–

• Three terms 8x + 4 , 6x - 2 and 2x + 7 are in A.P.

TO FIND :–

• Value of 'x'

SOLUTION :–

• If three numbers a , b , c are in A.P. then –

$\\ \longrightarrow \large { \blue{ \boxed{ \bold {2b = a + c}}}}$

• So that –

$\\ \implies { \bold {2(6x - 2) = (8x + 4)+ (2x + 7)}}$

$\\ \implies { \bold {12x -4 = 8x + 4+ 2x + 7}}$

$\\ \implies { \bold {12x -4 = 10x + 11}}$

$\\ \implies { \bold {12x - 10x = 4 + 11}}$

$\\ \implies { \bold {2x = 15}}$

$\\ \implies \large{ \blue{ \boxed{ \bold {x = \frac{15}{2} }}}}$