Question

Find the value of x for which (8x + 4), (6x – 2) and (2x + 7) are in AP​

Answer 1

Answer:

If a,b,c are in A.P  

     b=a+c/2

According to question 8x+4,6x-2,2x+7 are in A.P

        6x-2=(8x+4+2x+7)/2

        6x-2=10x+11/2

        2(6x-2)=10x+11

         12x-4=10x+11

          12x-10x=11+4

              2x=15

              x=15/2=7.5

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Since the terms are in A.P

6x-2-(8x+4)=(2x+7)-(6x-2)

=>6x-8x-2-4=2x-6x+7+2

=>-2x-6=-4x+9

=>2x=15

=>x=15/2